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锁定老帖子 主题:js数组的方法
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作者 | 正文 |
发表时间:2009-11-11
最后修改:2009-11-11
var a = [0,1,2];//用这三个数字创造一个新数组 var s1 = a.join();//s1 = "0,1,2" var s2 = a.join(", ");//s2 = "0, 1, 2" reverse()方法: var a = [0,1,2];//用这三个数字创造一个新数组 a.reverse();//a[0] = 2,a[1] = 1,a[2] = 0 var s = a.join();//s = "2,1,0" sort()方法: var a = ["banana","cherry","apple"];//用这三个字符串创造一个新数组 a.sort();//对数组元素排序,返回排序后的数组 var s = a.join();//s = "apple,banana,cherry" var a = [33,3,1111,222]; a.sort; //按字母排序 11111,222,33,4 a.sort(function(a,b){ //按数字排序 4,33,222,1111 return a-b; }); concat()方法: var a = [0,1,2];//用这三个数字创造一个新数组 a.concat([3,4]); //[0,1,2,3,4] a.concat(3,4); //[0,1,2,3,4] a.concat([3,4],[5,6]);//[0,1,2,3,4,5,6] a.concat(3,[4,[5,6]]);//[0,1,2,3,4,[5,6]]//不能递归展开元素为数组的数组 join()方法: var a = [0,1,2];//用这三个数字创造一个新数组 var s1 = a.join();//s1 = "0,1,2" var s2 = a.join(", ");//s2 = "0, 1, 2" slice()方法: var a = [0,1,2,3,4];//用这5个数字创造一个新数组 a.slice(0,3); //[0,1,2] a.slice(3); //[3,4] a.slice(1,-1);//[1,2,3] splice()方法: var a = [0,1,2,3,4];//用这5个数字创造一个新数组 a.splice(4); //返回[4]a是[0,1,2,3] a.splice(1,2); //返回[1,2]a是[0,3] a.splice(1,1); //返回[3]a是[0] var a = [0,1,2,3,4];//用这5个数字创造一个新数组 a.splice(2,0,'a','b');//返回[]a是[0,1,'a','b',2,3,4] a.splice(2,2,[1,2],3);//返回时['a','b'],a是[0,1,[1,2],3,3,4] 声明:ITeye文章版权属于作者,受法律保护。没有作者书面许可不得转载。
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